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Question

Solve : cos6Asin6A=cos2A(114sin22A)

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Solution

cos6Asin6A

=(cos2A)3(sin2A)3

=[cos2Asin2A][cos4A+cos2Asin2A+sin4A]

=cos2A[cos4A+sin4A+2cos2Asin2Acos2Asin2A]

=cos2A[(cos2Asin2A)2sin2Acos2A]

=cos2A(14sin2Acos2A4)

=cos2A(1(2sin2Acos2A)24)

=cos2A(1sin22A4)

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