Question

Solve
$\frac{x}{5}+\frac{y}{3}=\frac{x}{4}-\frac{y}{3}-\frac{3}{20}=0$

Answer 1

$\begin{array}{c}\frac{x}{5}+\frac{y}{3}=\frac{x}{4}-\frac{y}{3}-\frac{3}{20}=0\\ \Rightarrow \frac{x}{5}+\frac{y}{3}=0\\ 3x+5y=\mathrm{0....}\left(1\right)\\ and\\ \Rightarrow \frac{x}{4}-\frac{y}{3}=\frac{3}{20}\\ \Rightarrow 3x-4y=\frac{9}{5}......\left(2\right)\\ Substracteq\left(1\right)from\left(2\right)\\ 3x+5y=0\\ \frac{3x-4y=\frac{9}{5}}{9y=-\frac{9}{5}}\\ y=-\frac{1}{5}\\ Puttingy=-\frac{1}{5}inequation\left(1\right)\\ \Rightarrow 3x-5\times \frac{1}{5}=0\\ \Rightarrow 3x-1=0\\ \Rightarrow x=\frac{1}{3}\end{array}$