wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve: xaxb+xbxa=ab+ba

Open in App
Solution

xaxb+xbxa=ab+ba
(xa)2+(xb)(xa)(xb)=a2+b2ab
ab[x2+a22xa+x2+b22xb]=(a2+b2)[x2x(a+b)+ab]
ab[2x2+a2+b22x(a+b)]=(a2+b2)[x2x(a+b)+ab]
2ab x22x(a+b)ab+ab(a2+b2)=(a2+b)x2x(a+b)(a2+b2)+ab(a2+b2)
x2(a2+b22ab)x(a+b)(a2+b2)+2(a+b)abx=0
x2(ab)2x(a+b)[a2+b22ab2]=0
x2(ab)2x(a+b)[ab]2=0
x2x(a+b)=0
x(x(a+b))=0
x=0, a+b

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Expression formation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon