Question

Solve :
$\underset{x\to 2}{lim}\frac{\sqrt{1+}\sqrt{2+x}-\sqrt{3}}{x-2}$

Answer 1

$\underset{x\to \alpha }{lim}\frac{\sqrt{1}+\sqrt{2+x}-\sqrt{3}}{x-\alpha }$

Wrong question there should be

$\underset{x\to \alpha }{lim}\frac{1+\sqrt{2+x}-3}{x-\alpha }\left(\frac{0}{0}\right)$

$\underset{x\to \alpha }{lim}\frac{\frac{1}{2\sqrt{2+n}}}{1}$

$=\frac{1}{4}$