Solve each of the following equation by using the method of completing the square:
$3 x^{2} - 2 x - 1 = 0$

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Solution

Given,

$3 x^{2} - 2 x - 1 = 0$

$3 x^{2} - 3 x + x - 1 = 0$

$3 x (x - 1) + 1 (x - 1) = 0$

$(x - 1) (3 x + 1) = 0$

$∴ x = 1, - \frac{1}{3}$

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