CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Solve each of the following quadratic equations:

12a+b+2x=12a+1b+12x               [CBSE 2013]


Solution

12a+b+2x=12a+1b+12x12a+b+2x-12x=12a+1b2x-2a-b-2x2x2a+b+2x=2a+b2ab-2a+b4x2+4ax+2bx=2a+b2ab
4x2+4ax+2bx=-2ab4x2+4ax+2bx+2ab=04xx+a+2bx+a=0x+a4x+2b=0
x+a=0 or 4x+2b=0x=-a or x=-b2
Hence, -a and -b2 are the roots of the given equation.

Mathematics
RS Aggarwal (2018)
Standard X

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image