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Question

Solve each of the following quadratic equations: 
22x3.2(x+2)+32=0
 


Solution

22x3.2x+2+32=0(2x)23×2x×22+32=0(2x)212×2x+32=0Let  a=2xa212a+32=0a28a4a+32=0a(a8)4(a8)=0(a8)(a4)=0a=8  or  a=4

Case (i):

a=82x=82x=23x=3

Case (ii):

a=42x=42x=22x=2

So x = 3 or 2


Mathematics
Secondary School Mathematics X
Standard X

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