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Question

Solve each of the following quadratic equations: 
3(x+2)+3x=10


Solution

Given; 

3x+2+3x=103x.32+13x=109.3x+13x=109.3x.3x+13x=109(3x)2+1=10.3x9(3x)210.3x+1=0

Put z=3x

9z210z+1=09z29zz+1=09z(z1)1(z1)=0(9z1)(z1)=09z1=0  or  z1=0z=19  or  z=1

3x=19  or  3x=13x=32  or  3x=30x=2  or  0

Thus, the values of x are 0 or – 2.

 
 


Mathematics
Secondary School Mathematics X
Standard X

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