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Question

Solve each of the following quadratic equations: 
abx2+(b2ac)xbc=0


Solution

Consider,abx2+(b2ac)xbc=0
⇒ abx2 + b2x – acx – bc = 0
⇒ bx (ax + b) – c(ax + b) = 0
⇒ (ax + b)(bx – c) = 0

⇒ (ax + b) = 0 or (bx – c) = 0
⇒ ax = – b or bx = c ​​​​​​​
x equals fraction numerator negative b over denominator a space end fraction x equals c over b


Mathematics
Secondary School Mathematics X
Standard X

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