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Question

Solve each of the following systems of equations by using the method of cross multiplication:

x+2y+1=0,

2x3y12=0.

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Solution

x+2y+1=0……….(i)

2x3y12=0……….. (ii)

Here a1=1,b1=2,c1=1

a2=2,b2=3,c2=12

By cross multiplication method,

x24+3=y122=134

x21=y14=17

Now,

x21=17

=x=3

And,

y14=17

=y=2

The solution of the given system of equation is 3 and -2 respectively.


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