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Question

Solve for x and y:

7(y+3)2(x+2)=14,4(y2)+3(x3)=2

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Solution

The given system of equation is

7(y+3)2(x+2)=14…………………………. (i)

4(y2)+3(x3)=2………………………………..(ii)

From(i)

7y+212x4=14

7y=14+421+2x

=y=2x37

From(ii)

=4y8+3x9=2

=4y+3x172=0

=4y+3x19=0..(iii)

Substituting the value of y in equation (iii)

=4(2x37)+3x19=0

=8x12+21x133=0

=29x=145

=x=5

Putting the value of x in the above equation

=y=1

The value of x and y are 5 and 1 respectively


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