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Question

Solve for x and y:
3x25y3+2=0
x3+y2=216

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Solution

(3x2)(5y3)+2=0(1.)(x3)+(y2)=(1316)(2.)multiplyequation(1)by(29),weget(x3)(10y27)+(49)=0(1.)nowsubtracteqn(1)(2),weget(10y27)(y2)+(49)(136)=0(83918)=(20y+27y54)(3118)=(47y54)y=(31×347)=(9347)x=((136)(y2))×3=((136)+(9394))×=((1222+558)×36×94)=(89094)=(44547)


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