Solve for x where x€R |x^2-x-6| = x+2.

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Solve for x:

$\sqrt{x^{2} + x - 6} - x + 2 = \sqrt{x^{2} - 7 x + 10}, x ϵ R$

x :

x^{2} - 5 x + 6 = 0

x

\frac{2}{x^{2}} - \frac{1}{x} = 6

\sqrt{13 - 18 tan x} = 6 tan x - 3

- 2 π < x < 2 π

\frac{1}{x - 2} + \frac{2}{x - 1} = \frac{6}{x}

x \neq 1, 2

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