Solve: 3x+y+2x−y and 9x+y−4x−y=1
3x+y+2x−y=1....(1)
9x+y−4x−y=1....(2)
3(x−y)+2(x+y)=(x+y)(x−y)
3x−3y+2x+2y=x2−y2
5x−y=x2−y2....(3)
9(x−y)−4(x+y)=(x+y)(x−y)
9x−9y−4x−4y=x2−y2
5x−13y=x2−y2...(4)
subtracting equation (4) and (3)
5x−y=x2−y2
5x−13y=x2−y2
we get
12y=0
y=0
put in equation (3)
5x−0=x2−0
5x=x2
x=5