Solve
5(x−1)+1(y−2)=2
6(x−1)−3(y−2)=1 [4 MARKS]
Concept : 1 Mark
Application : 1 Mark
Calculation : 2 Marks
Given equations are,
5(x−1)+1(y−2)=2……(i)
6(x−1)−3(y−2)=1……(ii)
Let, 1(x−1)=p & 1(y−2)=q
Then equations (i) and (ii) reduces to,
5p+q=2……(iii)
6p–3q=1……(iv)
Equation (iii)×3 gives
15p+3q=6……(v)
Adding (iv) and (v) we get,
6p–3q+15p+3q=1+6
21p=7⇒p=13
Substituting value of p in (iv)
6p–3q=1
6(13)–3q=1
q=13
Now, p=13⇒1(x−1)=13
⇒x−1=3∴x=4
and q=13⇒1(y−2)=13
⇒y−2=3∴y=5
∴x=4,y=5