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Question

Solve

5(x1)+1(y2)=2

6(x1)3(y2)=1 [4 MARKS]

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Solution

Concept : 1 Mark
Application : 1 Mark
Calculation : 2 Marks

Given equations are,

5(x1)+1(y2)=2(i)

6(x1)3(y2)=1(ii)

Let, 1(x1)=p & 1(y2)=q

Then equations (i) and (ii) reduces to,

5p+q=2(iii)

6p3q=1(iv)

Equation (iii)×3 gives

15p+3q=6(v)

Adding (iv) and (v) we get,

6p3q+15p+3q=1+6

21p=7p=13

Substituting value of p in (iv)

6p3q=1

6(13)3q=1

q=13

Now, p=131(x1)=13

x1=3x=4

and q=131(y2)=13

y2=3y=5

x=4,y=5


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