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Question

Solve

5(x1)1(y2) = 2

6(x1)3(y2) = 1


Solution

1(x1) = p & 1(y2) = q

5 p + q = 2 ----------- (1)

Equation (1) × 3 gives

15 p + 3q = 6

6 p – 3q = 1 ----------- (2)

Solving equation (1) and (2), we get

p = 13, q =  13

Hence   x = 4, y = 5

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