Solve: 67-12.
We have, 67-12
To solve the above equation we need to find L.C.M of the denominator.
The L.C.M of 7 and 2=2×7=14
6×27×2-1×72×7=1214-714=514
Hence, the final answer is 514.
{1(sec2θ−cos2θ)+1(cosec2θ−sin2θ)}(sin2θcos2θ)=1−sin2θcos2θ2+sin2θcos2θ
Determine whether the following numbers are in proportion or not:
13,14,16,17
The sum of the series 23!+45!+67!+... to ∞ = ae. Find (a+3)2.
If f=x1+x2+13(x1+x2)3+15(x1+x2)5+... to ∞ and g=x−23x3+15x5+17x7−29x9+..., then f=d×g. Find 4d.