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Question

Solve :
i) 3x226x+2=0
ii) 23x25x+3=0
iii) x2+x+2=0

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Solution

(i) 3x226x+2=0 3×2=6
3x246x+2=0 6+6=26
3x[3x2]2[3x2]=0
(3x2][3x2]=0
(3x2)2=0
x=23
x=23
(ii) 23x25x+3=0 23×3=6
23x22x3x+3=0 6×1=6 2×3=6
2x[3x1]3[3x1]=0 61=5 2+3=5
[3x1][2x3]=0
x=32 or x=13.
(iii) x2+x+2=0 2×1=2
b24ac
124(2)7<0
x2+x+2=0 has no real roots as b24ac<0.

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