The correct option is B p=8, 4 P2 #8722;12P+32 ...

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Expansion of (a - b)^2

Solve: p2-1...

Question

Solve: $p^{2} - 12 p + 32 = 0$

p = - 8, 4

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p = 8, 4

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p = 8, - 4

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p = - 8, - 4

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Solution

The correct option is B $p = 8, 4$

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Similar questions

4 p^{2} + 7 = 12 p

(p + q) (p - q) (p^{2} + q^{2}) (p^{4} + q^{4}) (p^{8} + q^{8})

Solve: $p^{2} - 12 p + 32 = 0$ .

P

x

4 (2 - x) - 8 = 0

4 x + 5 (P - 1) = 34

P

2 \times 2

[\begin{matrix} 1 & 0 \end{matrix}] P = - \frac{1}{\sqrt{2}} [\begin{matrix} 1 & 1 \end{matrix}]

[\begin{matrix} 0 & 1 \end{matrix}] P = \frac{1}{\sqrt{2}} [\begin{matrix} - 1 & 1 \end{matrix}]

0

I

2

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