Solve the equation : 2x + 6 + 1x - 2 = 10

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Solution

The correct option is B
2

2x + 6 + 1x - 2 = 10

$\Rightarrow$ 3x + 4=10

$\Rightarrow$ 3x = 10 - 4 [when +4 is transposed to RHS it becomes -4]

$\Rightarrow$ 3x=6

Divide both the sides by 3. we get x=2

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Solve the equation : 2x + 6 + 1x - 2 = 10

The correct option is B 2 2x + 6 + 1x - 2 = 10 ⇒ 3x + 4=10 ⇒ 3x = 10 - 4 [when +4 is transposed to RHS it becomes -4] ⇒ 3x=6 Divide both the sides by 3. we get x=2

The correct option is B
2

2x + 6 + 1x - 2 = 10

$\Rightarrow$ 3x + 4=10

$\Rightarrow$ 3x = 10 - 4 [when +4 is transposed to RHS it becomes -4]

$\Rightarrow$ 3x=6

Divide both the sides by 3. we get x=2