Given equation is
2x−(13)=(15)−xTo find out: The value of x
Transporting the constant term to RHS and the variable x to the LHS, we get:
2x+x=(15)+(13)
⇒3x=(3+515)
⇒3x=(815)
⇒x=(845)
∴ x=845 is the solution of the given equation.
Let us now substitute the value of x in the equation to verify the solution.
(i) Substituting the value on LHS:
2×845−(13)
⇒1645−13
⇒16−1545
⇒145....(1)
(ii) Substituting the value on RHS:
15−845
⇒9−845
⇒145....(2)
From (1) and (2), we get, LHS = RHS.
Hence, it is verified that the obtained solution is correct.