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Question

Solve the following equation :

4(y+2)5=7+5y13


Solution

4(y+2)5=7+5y13 4y+85=91+5y13               by cross multiplying 13(4y+8)=5(91+5y) 52y+104=455+25y 52y25y=455104 27y=351 y=35127 y=13


Mathematics
Concise Mathematics
Standard VIII

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