Question

Solve the following equations.
$(x^2-1)\sqrt{2x-1}=0$

Answer 1

Given equation $(x^2-1)\sqrt{2x-1}$=0

$(x^2-1)=0$

$x^2=1$

$x=+1,-1$

now,

$\sqrt{2x-1}$=0

squaring both side we have,

$2x-1=0$

so $x=\frac{1}{2}$

now $x=1,-1,\frac{1}{2}$ hence this the answer