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Question

Solve the following inequation and graph the solution set on the number line. 2x3<x+23x+5,xϵR.

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Solution

2x3<x+23x+5
Let's break this up into two parts.....
First.......
2x3<x+2 ........ (add 3 to both sides)
2x<x+5 ........ (subtract x from both sides)
x<5
Secondly.......
x+23x+5
(subtract 5 from both sides)
x33x ......... (subtract x from both sides)
3<=2x ....... (divide both sides by 2)
32x (which also means x32)
Thus.........32x<5
Or in interval notation...... [32,5)
Try picking some values "outside" this interval. You'll find that they won't satisfy both inequalities!!


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