Solve the following non-homogeneous system of linear equations by determinant method.
$2 x + y - z = 4$
$x + y - 2 z = 0$
$3 x + 2 y - 3 z = 4$

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Solution

The determinant form of given equations is $∣ ∣ ∣ ∣ \begin{matrix} 2 & 1 & - 1 1 & 1 & - 2 3 & 2 & - 3 \end{matrix} ∣ ∣ ∣ ∣$ and the determinant value is $D = 0$
Sice the value of $D$ is zero , we get infinite solutions

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Similar questions

2 x + 3 y - z = 0

x - y - 2 z = 0

3 x + y + 3 z = 0

2 x + 2 y + z = 5

x - y + z = 1

3 x + y + 2 z = 4

x + y + 3 z = 4; 2 x + 2 y + 6 z = 7; 2 x + y + z = 10

3 x - 2 y + 3 z = 8

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4 x - 3 y + 2 z = 4

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