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Question

Solve the following pair of equation

5x1 + 1y2 = 2

6x1 - 3y2 = 1


A

4,5

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B

5,3

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C

1/3, 1/3

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D

None of these

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Solution

The correct option is A

4,5


If we substitute 1x1 as p and 1y2as q in the given equations. We get the equations as

5p+q=2

6q-3q=1

Now we can solve the pair of equation by method of elimination.

15p+3q=6

6p-3q=1

Adding both

p= 13

Now by substituting the value in one of the equation we find q= 13

AS we have assumed p = 1x1

Therefore, 1x1 = 13

→ x = 4

Similarly we assumed q = 1y2

1y2 = 13

→ y - 2 = 3

→ y = 5

Thus x=4, y=5


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