    Question

# Solve the following pair of equations:4x+6y=15 and 6x−8y=14

A
x=5;y=6
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B
x=3;y=2
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C
x=7;y=4
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D
x=0;y=6
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Solution

## The correct option is C x=3;y=2The equation 4x+6y=15 can be solved as: 4x+6y=15⇒4xy+6y=15⇒4xy+6=15y.........(1)The equation 6x−8y=14 can be solved as: 6x−8y=14⇒6xy−8y=14⇒6xy−8=14y.........(2)Multiply the equation 1 by 3 and equation 2 by 2. Then we get the equations:12xy+18=45y.........(3)12xy−16=28y.........(4)Subtract Equation 4 from equation 3 to eliminate xy, because the coefficients of xy are same. So, we get(12xy−12xy)+(18+16)=45y−28yi.e. 17y=34i.e. y=2Substituting this value of y in the equation 1, we get8x+6=30 i.e. 8x=30−6=24i.e. x=3Hence, the solution of the equations is x=3,y=2.  Suggest Corrections  0      Similar questions
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