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Question

Solve the following problem.
When two resistors are connected in series, their effective resistance is 80 Ω. When they are connected in parallel, their effective resistance is 20 Ω. What are the values of the two resistances?

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Solution

Consider two resistors of resistances R1,R2 respectively.
When they are in series connection,R1+R2=80
When they are in parallel connection,R1R2R1+R2=20
(80R2)(R2)80=20
(R2)280R2+1600=0
Applying Sree Dharacharya Rule of Quadratic Equation,
R2=80+8024×1×16002×1
R2=40Ω
R1=40Ω

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