Question

Solve the following quadratic equation $a^2{b}^2{x}^2+b^{2}x-a^{2}x-1=0$

Answer 1

$a^2{b}^2{x}^2+b^{2}x-a^{2}x-1=0$

$b^{2}x(a^{2}x+1)-1(a^{2}x+1)=0$

$(a^{2}x+1)(b^{2}x-1)=0$

$x=\frac{-1}{a^2},\frac{1}{b^2}$