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Question

Solve the following quadratic equation by factorization.
3x+1+4x1=294x1;x1,1,14
 


Solution

3x+1+4x1=294x1;x1,1,14

3(x1)+4(x+1)(x+1)(x1)=294x1

3x3+4x+4(x21)=294x1

7x+1(x21)=294x1

(7x+1)(4x1)=29(x21)

28x27x+4x1=29x229

28x23x1=29x229
x2+3x28=0

x24x+7x28=0

x(x4)+7(x4)=0

(x+7)(x4)=0

x=7,4


Mathematics
RD Sharma
Standard X

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