Question

Solve the following quadratic equation by factorization, the roots are :$\sqrt{2},-3\sqrt{2}$
$x^2-4\sqrt{2x}+6=0$

• A. True
• B. False

Answer 1

The correct option is B False

$x^2-4\sqrt{2}x+6=0$

$\Rightarrow$ $x^2-3\sqrt{2}-\sqrt{2}x+6=0$

$\Rightarrow$ $x(x-3\sqrt{2})-\sqrt{2}(x-3\sqrt{2})=0$

$\Rightarrow$ $(x-3\sqrt{2})(x-\sqrt{2})=0$

$\Rightarrow$ $x-3\sqrt{2}=0$ and $x-\sqrt{2}=0$

$\Rightarrow$ $x=3\sqrt{2}$ and $x=\sqrt{2}$

$\therefore$ We can see roots given in question are incorrect.