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Question

Solve the following quadratic equations by factorization:

3x+1-12=23x-1, x-1, 13


Solution

3x+1-12=23x-16-x+12(x+1)=23x-16-x-12x+2=23x-15-x3x-1=22x+215x-5-3x2+x=4x+4-3x2+16x-5-4x-4=0-3x2+12x-9=03x2-12x+9=0x2-4x+3=0x2-3x-x+3=0x(x-3)-1(x-3)=0(x-1)(x-3)=0x-1=0 or x-3=0x=1 or x=3

Hence, the factors are 3 and 1.

Mathematics
RD Sharma (2016)
Standard X

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