Question

Solve the following quadratic equations by factorization method :
$x^2-4ax+4a^2-b^2=0$

Answer 1

$x^2-4ax+4a^2-b^2=0$

$⟹x^2-4ax+4a^2=b^2$

$⟹(x-2a{)}^2=b^2$

$\therefore x-2a=b$ and $x-2a=-b$

$\therefore x=2a+b$ and $x=-b+2a$