Question

Question 88

Solve the following question:

Write cubes of first three multiples of 3.

Answer 1

Since, the first three multiples of 3 are 3, 6 and 9.
Hence, the cubes of first three multiples of 3 are $(3{)}^3,(6{)}^3$ and $(9{)}^3$, i.e. 27, 216 and 729.