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Question

Solve the following system of equations:

x7+y3=5

x2y9=6


Solution

Given system of equations:
x7+y3=5 and x2y9=6
3x+7y21=5 and 9x2y18=6
3x+7y=105 .........(i)and
9x2y=108 .........(ii)
From 3×eq(i)eq(ii)
9x+21y9x+2y=315108
23y=207
y=20723
y=9
Substitute y=9 in equation(i), we get
3x+7(9)=1053x+63=1053x=10563
3x=42
x=423
x=14
Hence, the value of x and y is x=14,y=9.

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