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Question

Solve the linear equation:

x2−15=x3+14

A
x=3.2
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B
x=9
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C
x=2.7
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D
x=5
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Solution

The correct option is C x=2.7
Given, x215=x3+14

The denominators on two sides are 2,3,4 and 5.

Their LCM is 60.

Multiplying both sides by 60, we get

60×(x215)=60×(x3+14)

60×x260×15=60×x3+60×14

30x12=20x+15

30x20x=15+12

10x=27

x=2710

x=2.7

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