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Question

Solve the quadratic equation : a2b2x2+b2xa2x1=0.
[CBSE.2005,2008]

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Solution

Given,

a2b2x2+b2xa2x1=0

a2b2x2+(b2a2)x1=0

a=a2b2,b=(b2a2),c=1

x=(b2a2)±(b2a2)24a2b2(1)2a2b2

=(b2a2)±(b2a2)2+4a2b22a2b2

=(b2a2)±(a2+b2)2a2b2

x=1b2,1a2

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