Question

Solve the quadratic equations by factorization:-
$\left(2x+3\right)\left(3x-7\right)=0$

Answer 1

This is a product of two expressions that is equal to zero. Note that any x value that makes either (2x+3) or (3x−7) zero, will make their product zero.

So now by putting $(2x+3)$ and $(3x-7)$ equal to zero, we get

$2x+3=0$

$2x+3-3=0-3$

$2x=-3$

$x=-\frac{3}{2}$

similarly,

$3x-7=0$

$x=\frac{7}{3}$

So now substituting either x=-3/2 or x=7/3 into the equation will result in the true statement 0=0, so they are both solutions to the equation.