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Question

Solve the system of inequalities: 15<3(x2)50.

A
13<x2
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B
23<x2
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C
23<x23
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D
13x23
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Solution

The correct option is B 23<x2
15<3(x2)50
If 15<3(x2)5
Multiply both sides by 5, we get
15×5<3(x2)5×5
75<3(x2)
75<3x6
Add 6 both sides, we get
75+6<3x6+6
69<3x
Dividing both sides by 3, we get
23<x ....... (i)
Also,
3(x2)50
3(x2)0
3x60
3x6
x2
Then 23<x2

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