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Standard VI

Physics

Thermal Equilibrium

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Q.22. A copper ball of mass 100 g is at a temperature T. It is dropped in a copper calorimeter of mass 100 g, filled with 170 g of water at room temperature. Subsequently, the temperature of the system is found to be 75 $°$ C. T is given by (Given : room temperature = 30 $°$ C, specific heat of copper = 0.1 cal $g^{- 1} ° C^{- 1}$ )
(a) 800 $°$ C
(b) 885 $°$ C
(c) 1250 $°$ C
(d) 825 $°$ C
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Solution

$D e a r s t u d e n t, I n t h i s c a s e, H e a t t a k e n w i l l b e e q u a l t o h e a t g i v e n s o, (100) (0.1) (T - 75) = (100) (0.1) (45) + (170) (1) (45) 10 (T - 75) = 450 + 7650 = 8100 T - 75 = 810 T = 885^{o} C R e g a r d s$

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Similar questions

Q. A copper ball of mass

100 g m

is at a temperature

T

. It is dropped in a copper calorimeter of mass

100 g m

, filled with

170 g m

of water at room temperature. Subsequently, the temperature of the system is found to be

75^{o} C

T

is equal to
(Given : Room temperature

= 30^{o} C

, specific heat of copper

= 0.1 c a l / g m^{o} C

)

Q. A copper ball of mass

100 g m

is at a temperature

T

. It is dropped in a copper calorimeter of mass

100 g m

, filled with

170 g m

of water at room temperature. Subsequently, the temperature of the system is found to be

75^{o} C

T

is given by :
(Given : room temperature

= 30^{o} C

, specific heat of copper

= 0.1 c a l / g m^{o} C

)

Q. A copper ball of mass

100 g m

is at a temperature

T

. It is dropped in a copper calorimeter of mass

100 g m

, filled with

170 g m

of water at room temperature. Subsequently, the temperature of the system is found to be

75^{o} C

T

is equal to
(Given : Room temperature

= 30^{o} C

, specific heat of copper

= 0.1 c a l / g m^{o} C

)

Q. A copper ball of mass

100 g m

is at a temperature

T

. It is dropped in a copper calorimeter of mass

100 g m

, filled with

170 g m

of water at room temperature. Subsequently, the temperature of the system is found to be

75^{o} C

T

is given by :

Q. An aluminium sphere of mass

0.047 k g

is heated to

100^{\circ} C

. It is dropped in a copper calorimeter of mass

0.14 k g

, containing

0.25 k g

of water at

20^{o} C

. The temperature of water rises to a steady state at

23^{o} C

. Calculate the specific heat of aluminium. specific heat of water

= 4.18 \times 10^{3} J k g^{- 1}^{o} C^{- 1}

, specific heat of copper

0.386 \times 10^{3} J k g^{- 1}^{o} C^{- 1}

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Dear student,In this case,Heat taken will be equal to heat givenso,(100)(0.1)(T–75)=(100)(0.1)(45)+(170)(1)(45)10(T−75)=450+7650=8100T−75=810T=885oCRegards

$D e a r s t u d e n t, I n t h i s c a s e, H e a t t a k e n w i l l b e e q u a l t o h e a t g i v e n s o, (100) (0.1) (T - 75) = (100) (0.1) (45) + (170) (1) (45) 10 (T - 75) = 450 + 7650 = 8100 T - 75 = 810 T = 885^{o} C R e g a r d s$