Solve this - - 1 2 - - 1 2 - - - 1 - - 1 - - - 1 2 - - 1 2 - - - 1 - - 1 to get - - - 1 - - - - - - 1 - - - - - - - - -

(α +1)^2/(α +1)^2 (α +1)(β +1) + (β +1)^2/(β +1)^2 (α +1)(β +1) = α +1/α β + β +1/β α = α β/α β L.H.S : #160; (α +1)^2/(α #160; +1)^2 ( ...

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Absolute Value Function

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Question

Solve this $\frac{(α + 1)^{2}}{(α + 1)^{2} - (α + 1) (β + 1)} + \frac{(β + 1)^{2}}{(β + 1)^{2} - (α + 1) (β + 1)}$ to get $= \frac{α + 1}{α - β} + \frac{β + 1}{β - α} = \frac{α - β}{α - β}$

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Solution

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(α + 1) (β - 1) + (β + 1) (α - 1) α + (α - 1) (β - 1) = 0

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