Question

Solve using distributive property of multiplication.
$\left(\begin{array}{c}\frac{-11}{8}\times \frac{14}{5}\end{array}\right)-\left(\begin{array}{c}\frac{-11}{8}\times \frac{9}{5}\end{array}\right)$

• A. $\frac{-11}{8}$
• B. $\frac{13}{9}$
• C. $\frac{7}{9}$
• D. $\frac{8}{9}$

Answer 1

The correct option is A $\frac{-11}{8}$

$\left(\begin{array}{c}\frac{-11}{8}\times \frac{14}{5}\end{array}\right)-\left(\begin{array}{c}\frac{-11}{8}\times \frac{9}{5}\end{array}\right)$

$=\frac{11}{-8}\left(\begin{array}{c}\frac{14}{5}-\frac{9}{5}\end{array}\right)=\frac{11}{-8}\times \left(\begin{array}{c}\frac{14-9}{5}\end{array}\right)$

$=\frac{-11}{8}\times \frac{5}{5}=\frac{-11}{8}\times 1=\frac{-11}{8}$