Solve using quadratic formula:-
(1) $p^{2} c^{2} + (p^{2} - q^{2}) x - q^{2} = 0$
(2) $9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a + 2 b^{2})$

Open in App

Solution

(1)

$p^{2} c^{2} + (p^{2} - q^{2}) x - q^{2} = 0$

$(p^{2} - q^{2}) x = - c^{2} p^{2} + q^{2}$

$x = \frac{- c^{2} p^{2} + q^{2}}{p^{2} - q^{2}}$

(2)

$9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a + 2 b^{2}) = 0$

$9 x^{2} - (9 a + 9 b) x + 2 a^{2} + 5 a + 2 b^{2} = 0$

$x_{1, 2} = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$

$x = \frac{(9 a + 9 b) \pm \sqrt{(9 a + 9 b)^{2} - 4 (9) (2 a^{2} + 5 a + 2 b^{2})}}{2 (9)}$

$x = \frac{3 a + 3 b \pm \sqrt{a^{2} + 18 a b - 20 a + b^{2}}}{6}$

Suggest Corrections

Similar questions

p^{2} c^{2} + (p^{2} - q^{2}) x - q^{2} = 0

Solve the following quadratic equation using quadratic formula .

$9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a b + 2 b^{2}) = 0$

9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a b + 2 b^{2}) = 0

9 x^{2} - 9 (a + b) + (2 a^{2} + 5 a b + 2 b^{2}) = 0

9 x^{2} - 9 (a + b) x + (2 a^{2} + 5 a b + 2 b^{2}) = 0

Join BYJU'S Learning Program