Solve: $x^{2} + 6 x - 16$

Open in App

Solution

$x^{2} + 6 x - 16$
$= x^{2} + 8 x - 2 x - 16$
$= x (x + 8) - 2 (x + 8)$
$= (x + 8) (x - 2)$
$∴ x^{2} + 6 x - 16 = (x + 8) (x - 2)$ .

Suggest Corrections

Similar questions

x^{2} - 6 x = 16

(i) x^{2} - 5 x = 0 (i i) x^{2} + 6 x = 27 (i i i) 9 x^{2} + 16 = - 24 x (i v) 121 = x^{2}

{log}_{\frac{- x^{2} - 6 x}{10}} (sin 3 x + sin x) = {log}_{\frac{- x^{2} - 6 x}{10}} (sin 2 x)

x^{2} + 2 \sqrt{x^{2} + 6 x} = 24 - 6 x

\frac{2 x - 2}{x^{2} - 36} - \frac{x - 2}{x^{2} - 6 x} = \frac{x - 1}{x^{2} + 6 x}

Join BYJU'S Learning Program