Question

# Some liquid is filled in a cylindrical vessel of radius $$R$$. Let $${ F }_{ 1 }$$ be the force applied by the liquid on the bottom of the cylinder. Now the same liquid is poured into a vessel of uniform square cross-section of side $$R$$. Let $${ F }_{ 2 }$$ be the force applied by the liquid on the bottom of this new vessel. (Neglect atmosphere pressure). Then

A
F1=πF2
B
F1=F2π
C
F1=πF2
D
F1=F2

Solution

## The correct option is D $${ F }_{ 1 }={ F }_{ 2 }$$Force applied on the base is equal to the weight of the liquid, since in both cases same liquid has been poured in the container, it will exert same force on the base of the container.$$F_1 = F_2$$Physics

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