Some steam at 100 - C is passed into 1-1 kg of water contained in a calorimeter of water equivalent 0-02 kg at 15 - C so that the temperature of the calorimeter and its contents rises to 80 - C- What is the mass of steam condensing in kg

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Standard IX

Physics

Physical Quantities and Measurement

Some steam at...

Question

Some steam at $100^{\circ} C$ is passed into $1.1 k g$ of water contained in a calorimeter of water equivalent $0.02 k g$ at $15^{\circ} C$ so that the temperature of the calorimeter and its contents rises to $80^{\circ} C$ . What is the mass of steam condensing (in $k g$ )

0.130

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0.065

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0.260

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0.135

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Solution

The correct option is A $0.130$
Let the mass of steam= $x$
Heat released = Heat gained by water
$540 x + x \times 1 \times (100 - 80) = 1.1 \times 1 \times (80 - 15) + 0.02 \times 1 \times (80 - 15)$
$\Rightarrow 540 + 20 x = 65 (1.1 + 0.02) x = 0.13$

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Steam at $100^{o} C$ is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at $15^{o} C$ till the temperature of the calorimeter and its contents rises to $80^{o} C .$ The mass of the steam condensed in kg is

Q. Steam at

100^{\circ} C

is passed into 1.1 kg of water contained in a calorimeter of water equivalent 0.02 kg at

15^{\circ} C

till the temperature of the calorimeter and its contents rise at

80^{\circ} C

. The mass of the stem condensed in kilogram is

Specific heat of water = $1 k c a l / k g^{\circ} C$ , Latent heat of Vaporisation = $540 k c a l / k g$

latent heat of vaporization of water = $540 c a l k g^{-} 1$ , specific heat capacity of water = $10^{3} c a l k g^{-} 1^{\circ} C^{-} 1$

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Some steam at 100∘C is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15∘C so that the temperature of the calorimeter and its contents rises to 80∘C. What is the mass of steam condensing (in kg)

The correct option is A 0.130Let the mass of steam=xHeat released = Heat gained by water540x+x×1×(100−80)=1.1×1×(80−15)+0.02×1×(80−15)⇒540+20x=65(1.1+0.02)x=0.13

Some steam at $100^{\circ} C$ is passed into $1.1 k g$ of water contained in a calorimeter of water equivalent $0.02 k g$ at $15^{\circ} C$ so that the temperature of the calorimeter and its contents rises to $80^{\circ} C$ . What is the mass of steam condensing (in $k g$ )

The correct option is A $0.130$
Let the mass of steam= $x$
Heat released = Heat gained by water
$540 x + x \times 1 \times (100 - 80) = 1.1 \times 1 \times (80 - 15) + 0.02 \times 1 \times (80 - 15)$
$\Rightarrow 540 + 20 x = 65 (1.1 + 0.02) x = 0.13$