Sounds from two identical sources $S_{1} a n d S_{2}$ reach a point P directly in the same phase with net intensity $I_{0}$ .The power of S1 is now reduced to $64 %$ of its initial value, and the phase difference between $S_{1} a n d S_{2}$ is varied continuously. The maximum and minimum intensities now recorded at P are Imax and Imin respectively. Then

I_{m a x} = 0.36 I_{0}, I_{m i n} = 0.09 I_{0}

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I_{m a x} = 0.81 I_{0}, I_{m i n} = 0.01 I_{0}

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I_{m a x} = 0.64 I_{0}, I_{m i n} = 0.04 I_{0}

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I_{m a x} = 0.64 I_{0}, I_{m i n} = 0.36 I_{0}

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Solution

The correct option is B $I_{m a x} = 0.81 I_{0}, I_{m i n} = 0.01 I_{0}$
$I_{m a x} = (1 + 0.8)^{2} \frac{I_{0}}{4} = 0.81 I_{0}; I_{m i n} = (1 - 0.8)^{2} \frac{I_{0}}{4} = 0.01 I_{0}$

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Sounds from two identical sources $S_{1}$ and $S_{2}$ reach a point P directly in the same phase with net intensity $I_{0}$ . The power of $S_{1}$ is now reduced to 64% of its initial value, and the phase difference between $S_{1}$ and $S_{2}$ is varied continuously. The maximum and minimum intensities now recorded at P are $I_{m a x}$ and $I_{m i n}$ respectively. Then