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Q27. A construction worker's helmet slips and falls when he is 78.4 m above the ground. He hears the sound of the helmet bitting the ground 4.23 s after it slipped. Find the speed of sound in air.

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Solution

Dear Student

27.
Time taken by helmet to hit ground is

$s = u t + \frac{1}{2} g t^{2} t^{2} = \frac{2 s}{g} = \frac{2 \times 78.4}{9.8} = 16 t = 4 s S o t i m e t a k e n b y s o u n d t o r e a c h t o w o r k e r a g a i n 4.23 s - 4 = 0.23 s S p e e d o f s o u n d = d i s \tan c e / t i m e = 78.4 / 0.23 = 340.87 m / s$
Regards

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Q. A construction worker's helmet slips and falls when he is

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4.23

seconds after it slipped. Find the speed of sound (in SI units) in air.

Q. A construction worker’s helmet slips and falls down when he is

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above the ground. He hears the sound of the helmet hitting the ground

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A construction worker’s helmet slips and falls down when he is 78.4m above the ground. He hears the sound of the helmet hitting the ground 4.23 seconds after it has slipped. Find the speed of sound in air.

A construction worker’s helmet slips and falls down when he is $78.4 m$ above the ground. He hears the sound of the helmet hitting the ground $4.23$ seconds after it has slipped. Find the speed of sound in air. ( Acceleration due to gravity $9.8 m / s^{2}$ )

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Solve this: ​Q27. A construction worker's helmet slips and falls when he is 78.4 m above the ground. He hears the sound of the helmet bitting the ground 4.23 s after it slipped. Find the speed of sound in air.

Dear Student 27. Time taken by helmet to hit ground is s = ut +12gt2t2=2sg=2×78.49.8=16t = 4sSo time taken by sound to reach to worker again 4.23 s -4 =0.23sSpeed of sound =distance/time =78.4/0.23 =340.87 m/s Regards

Solve this:

Q27. A construction worker's helmet slips and falls when he is 78.4 m above the ground. He hears the sound of the helmet bitting the ground 4.23 s after it slipped. Find the speed of sound in air.