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Question

Specific volume of cylindrical virus particle is 6.02×102ccg, whose radius and length arc 7A respectively. If NA=6.02×1023, find molecular weight of virus.


Solution


Specific volume =6.02×102ccgm
So density =1specific volume=16.02×102gmcc
Volume of the cylinder =πr2h=π×7×7×10×1030m3
Hence, mass of one virus = density × volume
mass of avogadro number of virus = NA × mass of one virus = molecular weight of the virus.

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