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Standard IX

Physics

Speed of Sound vs Speed of Light

Speed of soun...

Question

Speed of sound wave in a gas is $v_{1}$ and tins speed of molecules of the gas at the same temperature is $v_{2}$ . Then :

v_{1} = v_{2}

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v_{1} < v_{2}

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v_{1} > v_{2}

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v_{1} \leq v_{2}

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Solution

The correct option is B $v_{1} < v_{2}$
$Explanation:-$

We know that

Speed of sound in the gas, $v_{1} = \sqrt{\frac{r R t}{M}}$

RMS speed of gas molecule, $v_{2} = \sqrt{\frac{3 R t}{M}}$

Here

$r < T$

$∴ v_{1} < v_{2}$

$Hence the correct option is B$

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Speed of sound wave in a gas is v1 and tins speed of molecules of the gas at the same temperature is v2. Then :

The correct option is B v1<v2Explanation:-We know thatSpeed of sound in the gas, v1=√rRtMRMS speed of gas molecule, v2=√3RtMHerer<T∴v1<v2Hence the correct option is B

Speed of sound wave in a gas is $v_{1}$ and tins speed of molecules of the gas at the same temperature is $v_{2}$ . Then :

The correct option is B $v_{1} < v_{2}$
$Explanation:-$

We know that

Speed of sound in the gas, $v_{1} = \sqrt{\frac{r R t}{M}}$

RMS speed of gas molecule, $v_{2} = \sqrt{\frac{3 R t}{M}}$

Here

$r < T$

$∴ v_{1} < v_{2}$

$Hence the correct option is B$